60% of the candies in Packet Q were cranberry candies and the rest were cherry candies. Packet R had 25% more cranberry candies than Packet Q and twice as many candies than the total number of candies in Packet Q. Find the percentage of the cherry candies in Packet R that would need to be transferred into Packet Q, so that there were an equal number of cranberry and cherry candies in Packet Q.

	Packet Q		Packet R
	Cranberry	Cherry	Cranberry	Cherry
	5 u		10 u
Before	3 u	2 u	3.75 u	6.25 u
Change		+ 1 u		- 1 u
After	3 u	3 u	3.75 u	5.25 u

60% = ⁶⁰₁₀₀ = ³₅
100 %+ 25% = 125%

 Total number of candies in Packet Q
= 3 u + 2 u
= 5 u

Total number of candies in Packet R
= 2 x 5 u 
= 10 u

Number of cranberry candies in Packet R
= 125% x 3 u
=  ¹²⁵₁₀₀ x 3 u
= 3.75 u

Number of cranberry candies in Packet R
= 10 u - 3.75 u
= 6.25 u

Number of cherry candies to be transferred from Packet R to Packet Q
= 3 u - 2 u
= 1 u

Percentage of candies to be transferred from Packet R
= ¹_6.25 x 100%
= 16%

Answer(s): 16%