80% of the turkish delights in Packet U were cranberry turkish delights and the rest were apricot turkish delights. Packet V had 30% more cranberry turkish delights than Packet U and twice as many turkish delights than the total number of turkish delights in Packet U. Find the percentage of the apricot turkish delights in Packet V that would need to be transferred into Packet U, so that there were an equal number of cranberry and apricot turkish delights in Packet U.

	Packet U		Packet V
	Cranberry	Apricot	Cranberry	Apricot
	5 u		10 u
Before	4 u	1 u	5.2 u	4.8 u
Change		+ 3 u		- 3 u
After	4 u	4 u	5.2 u	1.8 u

80% = ⁸⁰₁₀₀ = ⁴₅
100 %+ 30% = 130%

 Total number of turkish delights in Packet U
= 4 u + 1 u
= 5 u

Total number of turkish delights in Packet V
= 2 x 5 u 
= 10 u

Number of cranberry turkish delights in Packet V
= 130% x 4 u
=  ¹³⁰₁₀₀ x 4 u
= 5.2 u

Number of cranberry turkish delights in Packet V
= 10 u - 5.2 u
= 4.8 u

Number of apricot turkish delights to be transferred from Packet V to Packet U
= 4 u - 1 u
= 3 u

Percentage of turkish delights to be transferred from Packet V
= ³_4.8 x 100%
= 62.5%

Answer(s): 62.5%