At first, Jeremy, Xylia and Archie had some chocolate bars in the ratio 7 : 5 : 6 respectively. Jeremy had 392 chocolate bars. Then he gave all his chocolate bars to Xylia and Archie. After receiving the chocolate bars from Jeremy, Xylia and Archie had the same number of chocolate bars. How many chocolate bars did Xylia receive from Jeremy?

	Jeremy	Xylia	Archie	Total
Before	7x1 = 7 u	5x1 = 5 u	6x1 = 6 u	18x1 = 18 u
Change	- 7 u	+ 7 u
After	0	1x9 = 9 u	1x9 = 9 u	2x9 = 18 u

The total number of chocolate bars remains unchanged. Make the total number of chocolate bars the same.  LCM of 2 and 18 is 18.

Total number of chocolate bars = 18 u

Number of chocolate bars that Xylia had in the end 
= 18 u ÷ 2
= 9 u

Number of chocolate bars that Jeremy had at first = 7 u 

7 u = 392

1 u = 392 ÷ 7 = 56

Number of chocolate bars that Xylia received from Jeremy
= 9 u - 5 u
= 4 u
= 4 x 56
= 224

Answer(s): 224