At first, Sean, Nicole and Bobby had some chocolate bars in the ratio 8 : 6 : 7 respectively. Sean had 368 chocolate bars. Then he gave all his chocolate bars to Nicole and Bobby. After receiving the chocolate bars from Sean, Nicole and Bobby had the same number of chocolate bars. How many chocolate bars did Nicole receive from Sean?

	Sean	Nicole	Bobby	Total
Before	8x2 = 16 u	6x2 = 12 u	7x2 = 14 u	21x2 = 42 u
Change	- 8 u	+ 8 u
After	0	1x21 = 21 u	1x21 = 21 u	2x21 = 42 u

The total number of chocolate bars remains unchanged. Make the total number of chocolate bars the same.  LCM of 2 and 21 is 42.

Total number of chocolate bars = 42 u

Number of chocolate bars that Nicole had in the end 
= 42 u ÷ 2
= 21 u

Number of chocolate bars that Sean had at first = 8 u 

8 u = 368

1 u = 368 ÷ 8 = 46

Number of chocolate bars that Nicole received from Sean
= 21 u - 12 u
= 9 u
= 9 x 46
= 414

Answer(s): 414