At first, Sean, Jean and Warren had some sweets in the ratio 7 : 5 : 6 respectively. Sean had 364 sweets. Then he gave all his sweets to Jean and Warren. After receiving the sweets from Sean, Jean and Warren had the same number of sweets. How many sweets did Jean receive from Sean?
| |
Sean |
Jean |
Warren |
Total |
Before |
7x1 =
7 u |
5x1 =
5 u |
6x1 =
6 u |
18x1 =
18 u |
| Change |
- 7 u |
+ 7 u |
|
After |
0 |
1x9 =
9 u |
1x9 =
9 u |
2x9 =
18 u |
The total number of sweets remains unchanged. Make the total number of sweets the same. LCM of 2 and 18 is 18.
Total number of sweets = 18 u
Number of sweets that Jean had in the end
= 18 u ÷ 2
= 9 u
Number of sweets that Sean had at first = 7 u
7 u = 364
1 u = 364 ÷ 7 = 52
Number of sweets that Jean received from Sean
= 9 u - 5 u
= 4 u
= 4 x 52
= 208
Answer(s): 208
