At first, Oscar, Betty and Charlie had some sweets in the ratio 7 : 5 : 6 respectively. Oscar had 266 sweets. Then he gave all his sweets to Betty and Charlie. After receiving the sweets from Oscar, Betty and Charlie had the same number of sweets. How many sweets did Betty receive from Oscar?
| |
Oscar |
Betty |
Charlie |
Total |
Before |
7x1 =
7 u |
5x1 =
5 u |
6x1 =
6 u |
18x1 =
18 u |
| Change |
- 7 u |
+ 7 u |
|
After |
0 |
1x9 =
9 u |
1x9 =
9 u |
2x9 =
18 u |
The total number of sweets remains unchanged. Make the total number of sweets the same. LCM of 2 and 18 is 18.
Total number of sweets = 18 u
Number of sweets that Betty had in the end
= 18 u ÷ 2
= 9 u
Number of sweets that Oscar had at first = 7 u
7 u = 266
1 u = 266 ÷ 7 = 38
Number of sweets that Betty received from Oscar
= 9 u - 5 u
= 4 u
= 4 x 38
= 152
Answer(s): 152
