At first, Jenson, Eva and Ethan had some sweets in the ratio 5 : 3 : 4 respectively. Jenson had 340 sweets. Then he gave all his sweets to Eva and Ethan. After receiving the sweets from Jenson, Eva and Ethan had the same number of sweets. How many sweets did Eva receive from Jenson?
| |
Jenson |
Eva |
Ethan |
Total |
Before |
5x1 =
5 u |
3x1 =
3 u |
4x1 =
4 u |
12x1 =
12 u |
| Change |
- 5 u |
+ 5 u |
|
After |
0 |
1x6 =
6 u |
1x6 =
6 u |
2x6 =
12 u |
The total number of sweets remains unchanged. Make the total number of sweets the same. LCM of 2 and 12 is 12.
Total number of sweets = 12 u
Number of sweets that Eva had in the end
= 12 u ÷ 2
= 6 u
Number of sweets that Jenson had at first = 5 u
5 u = 340
1 u = 340 ÷ 5 = 68
Number of sweets that Eva received from Jenson
= 6 u - 3 u
= 3 u
= 3 x 68
= 204
Answer(s): 204
