At first, Bryan, Marion and Gabriel had some candy canes in the ratio 7 : 5 : 6 respectively. Bryan had 273 candy canes. Then he gave all his candy canes to Marion and Gabriel. After receiving the candy canes from Bryan, Marion and Gabriel had the same number of candy canes. How many candy canes did Marion receive from Bryan?

	Bryan	Marion	Gabriel	Total
Before	7x1 = 7 u	5x1 = 5 u	6x1 = 6 u	18x1 = 18 u
Change	- 7 u	+ 7 u
After	0	1x9 = 9 u	1x9 = 9 u	2x9 = 18 u

The total number of candy canes remains unchanged. Make the total number of candy canes the same.  LCM of 2 and 18 is 18.

Total number of candy canes = 18 u

Number of candy canes that Marion had in the end 
= 18 u ÷ 2
= 9 u

Number of candy canes that Bryan had at first = 7 u 

7 u = 273

1 u = 273 ÷ 7 = 39

Number of candy canes that Marion received from Bryan
= 9 u - 5 u
= 4 u
= 4 x 39
= 156

Answer(s): 156