At first, Bobby, Victoria and Simon had some sweets in the ratio 8 : 6 : 7 respectively. Bobby had 432 sweets. Then he gave all his sweets to Victoria and Simon. After receiving the sweets from Bobby, Victoria and Simon had the same number of sweets. How many sweets did Victoria receive from Bobby?

	Bobby	Victoria	Simon	Total
Before	8x2 = 16 u	6x2 = 12 u	7x2 = 14 u	21x2 = 42 u
Change	- 8 u	+ 8 u
After	0	1x21 = 21 u	1x21 = 21 u	2x21 = 42 u

The total number of sweets remains unchanged. Make the total number of sweets the same.  LCM of 2 and 21 is 42.

Total number of sweets = 42 u

Number of sweets that Victoria had in the end 
= 42 u ÷ 2
= 21 u

Number of sweets that Bobby had at first = 8 u 

8 u = 432

1 u = 432 ÷ 8 = 54

Number of sweets that Victoria received from Bobby
= 21 u - 12 u
= 9 u
= 9 x 54
= 486

Answer(s): 486