At first, Howard, Risa and Brandon had some sweets in the ratio 6 : 4 : 5 respectively. Howard had 258 sweets. Then he gave all his sweets to Risa and Brandon. After receiving the sweets from Howard, Risa and Brandon had the same number of sweets. How many sweets did Risa receive from Howard?
| |
Howard |
Risa |
Brandon |
Total |
Before |
6x2 =
12 u |
4x2 =
8 u |
5x2 =
10 u |
15x2 =
30 u |
| Change |
- 6 u |
+ 6 u |
|
After |
0 |
1x15 =
15 u |
1x15 =
15 u |
2x15 =
30 u |
The total number of sweets remains unchanged. Make the total number of sweets the same. LCM of 2 and 15 is 30.
Total number of sweets = 30 u
Number of sweets that Risa had in the end
= 30 u ÷ 2
= 15 u
Number of sweets that Howard had at first = 6 u
6 u = 258
1 u = 258 ÷ 6 = 43
Number of sweets that Risa received from Howard
= 15 u - 8 u
= 7 u
= 7 x 43
= 301
Answer(s): 301
