At first, Tim, Hazel and Luke had some sweets in the ratio 6 : 4 : 5 respectively. Tim had 282 sweets. Then he gave all his sweets to Hazel and Luke. After receiving the sweets from Tim, Hazel and Luke had the same number of sweets. How many sweets did Hazel receive from Tim?
| |
Tim |
Hazel |
Luke |
Total |
Before |
6x2 =
12 u |
4x2 =
8 u |
5x2 =
10 u |
15x2 =
30 u |
| Change |
- 6 u |
+ 6 u |
|
After |
0 |
1x15 =
15 u |
1x15 =
15 u |
2x15 =
30 u |
The total number of sweets remains unchanged. Make the total number of sweets the same. LCM of 2 and 15 is 30.
Total number of sweets = 30 u
Number of sweets that Hazel had in the end
= 30 u ÷ 2
= 15 u
Number of sweets that Tim had at first = 6 u
6 u = 282
1 u = 282 ÷ 6 = 47
Number of sweets that Hazel received from Tim
= 15 u - 8 u
= 7 u
= 7 x 47
= 329
Answer(s): 329
