At first, Julian, Zoe and Charlie had some sweets in the ratio 6 : 4 : 5 respectively. Julian had 222 sweets. Then he gave all his sweets to Zoe and Charlie. After receiving the sweets from Julian, Zoe and Charlie had the same number of sweets. How many sweets did Zoe receive from Julian?
| |
Julian |
Zoe |
Charlie |
Total |
Before |
6x2 =
12 u |
4x2 =
8 u |
5x2 =
10 u |
15x2 =
30 u |
| Change |
- 6 u |
+ 6 u |
|
After |
0 |
1x15 =
15 u |
1x15 =
15 u |
2x15 =
30 u |
The total number of sweets remains unchanged. Make the total number of sweets the same. LCM of 2 and 15 is 30.
Total number of sweets = 30 u
Number of sweets that Zoe had in the end
= 30 u ÷ 2
= 15 u
Number of sweets that Julian had at first = 6 u
6 u = 222
1 u = 222 ÷ 6 = 37
Number of sweets that Zoe received from Julian
= 15 u - 8 u
= 7 u
= 7 x 37
= 259
Answer(s): 259
