At first, Brandon, Jade and Oscar had some mochi balls in the ratio 8 : 6 : 7 respectively. Brandon had 416 mochi balls. Then he gave all his mochi balls to Jade and Oscar. After receiving the mochi balls from Brandon, Jade and Oscar had the same number of mochi balls. How many mochi balls did Jade receive from Brandon?
|
Brandon |
Jade |
Oscar |
Total |
Before |
8x2 = 16 u |
6x2 = 12 u |
7x2 = 14 u |
21x2 = 42 u |
Change |
- 8 u |
+ 8 u |
|
After |
0 |
1x21 = 21 u |
1x21 = 21 u |
2x21 = 42 u |
The total number of mochi balls remains unchanged. Make the total number of mochi balls the same. LCM of 2 and 21 is 42.
Total number of mochi balls = 42 u
Number of mochi balls that Jade had in the end
= 42 u ÷ 2
= 21 u
Number of mochi balls that Brandon had at first = 8 u
8 u = 416
1 u = 416 ÷ 8 = 52
Number of mochi balls that Jade received from Brandon
= 21 u - 12 u
= 9 u
= 9 x 52
= 468
Answer(s): 468