Container J and Container K had some detergent in the ratio 9 : 5. After 20 litres of detergent was transferred from Container J to Container K, the volume of detergent in Container K became 5 times as much as in Container J. How much detergent were there in the two containers in all?
| |
Container J |
Container K |
Total |
Before |
9x3 =
27 u |
5x3 =
15 u |
14x3 =
42 u |
| Change |
- 20 |
+ 20 |
|
After |
1x7 =
7 u |
5x7 =
35 u |
6x7 =
42 u |
The total volume of detergent in the containers remained unchanged. Make the total volume at first and in the end the same. LCM of 6 and 14 is 42.
Amount of detergent transferred from Container J to Container K
= 27 u - 7 u
= 20 u
20 u = 20
1 u = 20 ÷ 20 = 1
Total volume of detergent in two containers
= 42 u
= 42 x 1
= 42 ℓ
Answer(s): 42 ℓ
