Container Y and Container Z had some detergent in the ratio 9 : 4. After 46 litres of detergent was transferred from Container Y to Container Z, the volume of detergent in Container Z became 3 times as much as in Container Y. How much detergent were there in the two containers in all?
|
Container Y |
Container Z |
Total |
Before |
9x4 = 36 u |
4x4 = 16 u |
13x4 = 52 u |
Change |
- 46 |
+ 46 |
|
After |
1x13 = 13 u |
3x13 = 39 u |
4x13 = 52 u |
The total volume of detergent in the containers remained unchanged. Make the total volume at first and in the end the same. LCM of 4 and 13 is 52.
Amount of detergent transferred from Container Y to Container Z
= 36 u - 13 u
= 23 u
23 u = 46
1 u = 46 ÷ 23 = 2
Total volume of detergent in two containers
= 52 u
= 52 x 2
= 104 ℓ
Answer(s): 104 ℓ