Container H and Container J had some detergent in the ratio 7 : 5. After 39 litres of detergent was transferred from Container H to Container J, the volume of detergent in Container J became 2 times as much as in Container H. How much detergent were there in the two containers in all?
| |
Container H |
Container J |
Total |
Before |
7x1 =
7 u |
5x1 =
5 u |
12x1 =
12 u |
| Change |
- 39 |
+ 39 |
|
After |
1x4 =
4 u |
2x4 =
8 u |
3x4 =
12 u |
The total volume of detergent in the containers remained unchanged. Make the total volume at first and in the end the same. LCM of 3 and 12 is 12.
Amount of detergent transferred from Container H to Container J
= 7 u - 4 u
= 3 u
3 u = 39
1 u = 39 ÷ 3 = 13
Total volume of detergent in two containers
= 12 u
= 12 x 13
= 156 ℓ
Answer(s): 156 ℓ
