Container J and Container K had some sauce in the ratio 7 : 5. After 25 litres of sauce was transferred from Container J to Container K, the volume of sauce in Container K became 5 times as much as in Container J. How much sauce were there in the two containers in all?
| |
Container J |
Container K |
Total |
Before |
7x1 =
7 u |
5x1 =
5 u |
12x1 =
12 u |
| Change |
- 25 |
+ 25 |
|
After |
1x2 =
2 u |
5x2 =
10 u |
6x2 =
12 u |
The total volume of sauce in the containers remained unchanged. Make the total volume at first and in the end the same. LCM of 6 and 12 is 12.
Amount of sauce transferred from Container J to Container K
= 7 u - 2 u
= 5 u
5 u = 25
1 u = 25 ÷ 5 = 5
Total volume of sauce in two containers
= 12 u
= 12 x 5
= 60 ℓ
Answer(s): 60 ℓ
