Barrel G and Barrel H had some wine in the ratio 9 : 4. After 41 litres of wine was transferred from Barrel G to Barrel H, the volume of wine in Barrel H became 5 times as much as in Barrel G. How much wine were there in the two barrels in all?
| |
Barrel G |
Barrel H |
Total |
Before |
9x6 =
54 u |
4x6 =
24 u |
13x6 =
78 u |
| Change |
- 41 |
+ 41 |
|
After |
1x13 =
13 u |
5x13 =
65 u |
6x13 =
78 u |
The total volume of wine in the barrels remained unchanged. Make the total volume at first and in the end the same. LCM of 6 and 13 is 78.
Amount of wine transferred from Barrel G to Barrel H
= 54 u - 13 u
= 41 u
41 u = 41
1 u = 41 ÷ 41 = 1
Total volume of wine in two barrels
= 78 u
= 78 x 1
= 78 ℓ
Answer(s): 78 ℓ
