Container L and Container M had some detergent in the ratio 7 : 5. After 32 litres of detergent was transferred from Container L to Container M, the volume of detergent in Container M became 3 times as much as in Container L. How much detergent were there in the two containers in all?
| |
Container L |
Container M |
Total |
Before |
7x1 =
7 u |
5x1 =
5 u |
12x1 =
12 u |
| Change |
- 32 |
+ 32 |
|
After |
1x3 =
3 u |
3x3 =
9 u |
4x3 =
12 u |
The total volume of detergent in the containers remained unchanged. Make the total volume at first and in the end the same. LCM of 4 and 12 is 12.
Amount of detergent transferred from Container L to Container M
= 7 u - 3 u
= 4 u
4 u = 32
1 u = 32 ÷ 4 = 8
Total volume of detergent in two containers
= 12 u
= 12 x 8
= 96 ℓ
Answer(s): 96 ℓ
