Barrel M and Barrel N had some syrup in the ratio 7 : 5. After 36 litres of syrup was transferred from Barrel M to Barrel N, the volume of syrup in Barrel N became 3 times as much as in Barrel M. How much syrup were there in the two barrels in all?
| |
Barrel M |
Barrel N |
Total |
Before |
7x1 =
7 u |
5x1 =
5 u |
12x1 =
12 u |
| Change |
- 36 |
+ 36 |
|
After |
1x3 =
3 u |
3x3 =
9 u |
4x3 =
12 u |
The total volume of syrup in the barrels remained unchanged. Make the total volume at first and in the end the same. LCM of 4 and 12 is 12.
Amount of syrup transferred from Barrel M to Barrel N
= 7 u - 3 u
= 4 u
4 u = 36
1 u = 36 ÷ 4 = 9
Total volume of syrup in two barrels
= 12 u
= 12 x 9
= 108 ℓ
Answer(s): 108 ℓ
