Tank R and Tank S had some cooking wine in the ratio 9 : 5. After 31 litres of cooking wine was transferred from Tank R to Tank S, the volume of cooking wine in Tank S became 4 times as much as in Tank R. How much cooking wine were there in the two tanks in all?
| |
Tank R |
Tank S |
Total |
Before |
9x5 =
45 u |
5x5 =
25 u |
14x5 =
70 u |
| Change |
- 31 |
+ 31 |
|
After |
1x14 =
14 u |
4x14 =
56 u |
5x14 =
70 u |
The total volume of cooking wine in the tanks remained unchanged. Make the total volume at first and in the end the same. LCM of 5 and 14 is 70.
Amount of cooking wine transferred from Tank R to Tank S
= 45 u - 14 u
= 31 u
31 u = 31
1 u = 31 ÷ 31 = 1
Total volume of cooking wine in two tanks
= 70 u
= 70 x 1
= 70 ℓ
Answer(s): 70 ℓ
