Tank M and Tank N had some detergent in the ratio 7 : 4. After 20 litres of detergent was transferred from Tank M to Tank N, the volume of detergent in Tank N became 2 times as much as in Tank M. How much detergent were there in the two tanks in all?
| |
Tank M |
Tank N |
Total |
Before |
7x3 =
21 u |
4x3 =
12 u |
11x3 =
33 u |
| Change |
- 20 |
+ 20 |
|
After |
1x11 =
11 u |
2x11 =
22 u |
3x11 =
33 u |
The total volume of detergent in the tanks remained unchanged. Make the total volume at first and in the end the same. LCM of 3 and 11 is 33.
Amount of detergent transferred from Tank M to Tank N
= 21 u - 11 u
= 10 u
10 u = 20
1 u = 20 ÷ 10 = 2
Total volume of detergent in two tanks
= 33 u
= 33 x 2
= 66 ℓ
Answer(s): 66 ℓ
