Container R and Container S had some syrup in the ratio 7 : 5. After 28 litres of syrup was transferred from Container R to Container S, the volume of syrup in Container S became 3 times as much as in Container R. How much syrup were there in the two containers in all?
|
Container R |
Container S |
Total |
Before |
7x1 = 7 u |
5x1 = 5 u |
12x1 = 12 u |
Change |
- 28 |
+ 28 |
|
After |
1x3 = 3 u |
3x3 = 9 u |
4x3 = 12 u |
The total volume of syrup in the containers remained unchanged. Make the total volume at first and in the end the same. LCM of 4 and 12 is 12.
Amount of syrup transferred from Container R to Container S
= 7 u - 3 u
= 4 u
4 u = 28
1 u = 28 ÷ 4 = 7
Total volume of syrup in two containers
= 12 u
= 12 x 7
= 84 ℓ
Answer(s): 84 ℓ