Container A and Container B had some vinegar in the ratio 7 : 5. After 24 litres of vinegar was transferred from Container A to Container B, the volume of vinegar in Container B became 2 times as much as in Container A. How much vinegar were there in the two containers in all?
| |
Container A |
Container B |
Total |
Before |
7x1 =
7 u |
5x1 =
5 u |
12x1 =
12 u |
| Change |
- 24 |
+ 24 |
|
After |
1x4 =
4 u |
2x4 =
8 u |
3x4 =
12 u |
The total volume of vinegar in the containers remained unchanged. Make the total volume at first and in the end the same. LCM of 3 and 12 is 12.
Amount of vinegar transferred from Container A to Container B
= 7 u - 4 u
= 3 u
3 u = 24
1 u = 24 ÷ 3 = 8
Total volume of vinegar in two containers
= 12 u
= 12 x 8
= 96 ℓ
Answer(s): 96 ℓ
