Pail M and Pail N had some oil in the ratio 7 : 5. After 36 litres of oil was transferred from Pail M to Pail N, the volume of oil in Pail N became 2 times as much as in Pail M. How much oil were there in the two pails in all?
| |
Pail M |
Pail N |
Total |
Before |
7x1 =
7 u |
5x1 =
5 u |
12x1 =
12 u |
| Change |
- 36 |
+ 36 |
|
After |
1x4 =
4 u |
2x4 =
8 u |
3x4 =
12 u |
The total volume of oil in the pails remained unchanged. Make the total volume at first and in the end the same. LCM of 3 and 12 is 12.
Amount of oil transferred from Pail M to Pail N
= 7 u - 4 u
= 3 u
3 u = 36
1 u = 36 ÷ 3 = 12
Total volume of oil in two pails
= 12 u
= 12 x 12
= 144 ℓ
Answer(s): 144 ℓ
