Pail K and Pail L had some vinegar in the ratio 7 : 5. After 21 litres of vinegar was transferred from Pail K to Pail L, the volume of vinegar in Pail L became 2 times as much as in Pail K. How much vinegar were there in the two pails in all?
| |
Pail K |
Pail L |
Total |
Before |
7x1 =
7 u |
5x1 =
5 u |
12x1 =
12 u |
| Change |
- 21 |
+ 21 |
|
After |
1x4 =
4 u |
2x4 =
8 u |
3x4 =
12 u |
The total volume of vinegar in the pails remained unchanged. Make the total volume at first and in the end the same. LCM of 3 and 12 is 12.
Amount of vinegar transferred from Pail K to Pail L
= 7 u - 4 u
= 3 u
3 u = 21
1 u = 21 ÷ 3 = 7
Total volume of vinegar in two pails
= 12 u
= 12 x 7
= 84 ℓ
Answer(s): 84 ℓ
