Pail E and Pail F had some sauce in the ratio 7 : 5. After 20 litres of sauce was transferred from Pail E to Pail F, the volume of sauce in Pail F became 5 times as much as in Pail E. How much sauce were there in the two pails in all?
| |
Pail E |
Pail F |
Total |
Before |
7x1 =
7 u |
5x1 =
5 u |
12x1 =
12 u |
| Change |
- 20 |
+ 20 |
|
After |
1x2 =
2 u |
5x2 =
10 u |
6x2 =
12 u |
The total volume of sauce in the pails remained unchanged. Make the total volume at first and in the end the same. LCM of 6 and 12 is 12.
Amount of sauce transferred from Pail E to Pail F
= 7 u - 2 u
= 5 u
5 u = 20
1 u = 20 ÷ 5 = 4
Total volume of sauce in two pails
= 12 u
= 12 x 4
= 48 ℓ
Answer(s): 48 ℓ
