Container R and Container S had some sauce in the ratio 7 : 5. After 24 litres of sauce was transferred from Container R to Container S, the volume of sauce in Container S became 3 times as much as in Container R. How much sauce were there in the two containers in all?
| |
Container R |
Container S |
Total |
Before |
7x1 =
7 u |
5x1 =
5 u |
12x1 =
12 u |
| Change |
- 24 |
+ 24 |
|
After |
1x3 =
3 u |
3x3 =
9 u |
4x3 =
12 u |
The total volume of sauce in the containers remained unchanged. Make the total volume at first and in the end the same. LCM of 4 and 12 is 12.
Amount of sauce transferred from Container R to Container S
= 7 u - 3 u
= 4 u
4 u = 24
1 u = 24 ÷ 4 = 6
Total volume of sauce in two containers
= 12 u
= 12 x 6
= 72 ℓ
Answer(s): 72 ℓ
