Barrel G and Barrel H had some cooking wine in the ratio 9 : 5. After 20 litres of cooking wine was transferred from Barrel G to Barrel H, the volume of cooking wine in Barrel H became 5 times as much as in Barrel G. How much cooking wine were there in the two barrels in all?
| |
Barrel G |
Barrel H |
Total |
Before |
9x3 =
27 u |
5x3 =
15 u |
14x3 =
42 u |
| Change |
- 20 |
+ 20 |
|
After |
1x7 =
7 u |
5x7 =
35 u |
6x7 =
42 u |
The total volume of cooking wine in the barrels remained unchanged. Make the total volume at first and in the end the same. LCM of 6 and 14 is 42.
Amount of cooking wine transferred from Barrel G to Barrel H
= 27 u - 7 u
= 20 u
20 u = 20
1 u = 20 ÷ 20 = 1
Total volume of cooking wine in two barrels
= 42 u
= 42 x 1
= 42 ℓ
Answer(s): 42 ℓ
