Tank V and Tank W had some sauce in the ratio 7 : 4. After 48 litres of sauce was transferred from Tank V to Tank W, the volume of sauce in Tank W became 4 times as much as in Tank V. How much sauce were there in the two tanks in all?
| |
Tank V |
Tank W |
Total |
Before |
7x5 =
35 u |
4x5 =
20 u |
11x5 =
55 u |
| Change |
- 48 |
+ 48 |
|
After |
1x11 =
11 u |
4x11 =
44 u |
5x11 =
55 u |
The total volume of sauce in the tanks remained unchanged. Make the total volume at first and in the end the same. LCM of 5 and 11 is 55.
Amount of sauce transferred from Tank V to Tank W
= 35 u - 11 u
= 24 u
24 u = 48
1 u = 48 ÷ 24 = 2
Total volume of sauce in two tanks
= 55 u
= 55 x 2
= 110 ℓ
Answer(s): 110 ℓ
