Container Y and Container Z had some detergent in the ratio 9 : 4. After 28 litres of detergent was transferred from Container Y to Container Z, the volume of detergent in Container Z became 2 times as much as in Container Y. How much detergent were there in the two containers in all?
| |
Container Y |
Container Z |
Total |
Before |
9x3 =
27 u |
4x3 =
12 u |
13x3 =
39 u |
| Change |
- 28 |
+ 28 |
|
After |
1x13 =
13 u |
2x13 =
26 u |
3x13 =
39 u |
The total volume of detergent in the containers remained unchanged. Make the total volume at first and in the end the same. LCM of 3 and 13 is 39.
Amount of detergent transferred from Container Y to Container Z
= 27 u - 13 u
= 14 u
14 u = 28
1 u = 28 ÷ 14 = 2
Total volume of detergent in two containers
= 39 u
= 39 x 2
= 78 ℓ
Answer(s): 78 ℓ
