Container X and Container Y had some vinegar in the ratio 7 : 5. After 40 litres of vinegar was transferred from Container X to Container Y, the volume of vinegar in Container Y became 3 times as much as in Container X. How much vinegar were there in the two containers in all?
| |
Container X |
Container Y |
Total |
Before |
7x1 =
7 u |
5x1 =
5 u |
12x1 =
12 u |
| Change |
- 40 |
+ 40 |
|
After |
1x3 =
3 u |
3x3 =
9 u |
4x3 =
12 u |
The total volume of vinegar in the containers remained unchanged. Make the total volume at first and in the end the same. LCM of 4 and 12 is 12.
Amount of vinegar transferred from Container X to Container Y
= 7 u - 3 u
= 4 u
4 u = 40
1 u = 40 ÷ 4 = 10
Total volume of vinegar in two containers
= 12 u
= 12 x 10
= 120 ℓ
Answer(s): 120 ℓ
