Container X and Container Y had some sauce in the ratio 7 : 5. After 40 litres of sauce was transferred from Container X to Container Y, the volume of sauce in Container Y became 5 times as much as in Container X. How much sauce were there in the two containers in all?
| |
Container X |
Container Y |
Total |
Before |
7x1 =
7 u |
5x1 =
5 u |
12x1 =
12 u |
| Change |
- 40 |
+ 40 |
|
After |
1x2 =
2 u |
5x2 =
10 u |
6x2 =
12 u |
The total volume of sauce in the containers remained unchanged. Make the total volume at first and in the end the same. LCM of 6 and 12 is 12.
Amount of sauce transferred from Container X to Container Y
= 7 u - 2 u
= 5 u
5 u = 40
1 u = 40 ÷ 5 = 8
Total volume of sauce in two containers
= 12 u
= 12 x 8
= 96 ℓ
Answer(s): 96 ℓ
