Container M and Container N had some vinegar in the ratio 9 : 5. After 33 litres of vinegar was transferred from Container M to Container N, the volume of vinegar in Container N became 3 times as much as in Container M. How much vinegar were there in the two containers in all?
| |
Container M |
Container N |
Total |
Before |
9x2 =
18 u |
5x2 =
10 u |
14x2 =
28 u |
| Change |
- 33 |
+ 33 |
|
After |
1x7 =
7 u |
3x7 =
21 u |
4x7 =
28 u |
The total volume of vinegar in the containers remained unchanged. Make the total volume at first and in the end the same. LCM of 4 and 14 is 28.
Amount of vinegar transferred from Container M to Container N
= 18 u - 7 u
= 11 u
11 u = 33
1 u = 33 ÷ 11 = 3
Total volume of vinegar in two containers
= 28 u
= 28 x 3
= 84 ℓ
Answer(s): 84 ℓ
