Pail V and Pail W had some oil in the ratio 9 : 4. After 41 litres of oil was transferred from Pail V to Pail W, the volume of oil in Pail W became 5 times as much as in Pail V. How much oil were there in the two pails in all?
| |
Pail V |
Pail W |
Total |
Before |
9x6 =
54 u |
4x6 =
24 u |
13x6 =
78 u |
| Change |
- 41 |
+ 41 |
|
After |
1x13 =
13 u |
5x13 =
65 u |
6x13 =
78 u |
The total volume of oil in the pails remained unchanged. Make the total volume at first and in the end the same. LCM of 6 and 13 is 78.
Amount of oil transferred from Pail V to Pail W
= 54 u - 13 u
= 41 u
41 u = 41
1 u = 41 ÷ 41 = 1
Total volume of oil in two pails
= 78 u
= 78 x 1
= 78 ℓ
Answer(s): 78 ℓ
