Tank C and Tank D had some cooking wine in the ratio 7 : 5. After 46 litres of cooking wine was transferred from Tank C to Tank D, the volume of cooking wine in Tank D became 4 times as much as in Tank C. How much cooking wine were there in the two tanks in all?
| |
Tank C |
Tank D |
Total |
Before |
7x5 =
35 u |
5x5 =
25 u |
12x5 =
60 u |
| Change |
- 46 |
+ 46 |
|
After |
1x12 =
12 u |
4x12 =
48 u |
5x12 =
60 u |
The total volume of cooking wine in the tanks remained unchanged. Make the total volume at first and in the end the same. LCM of 5 and 12 is 60.
Amount of cooking wine transferred from Tank C to Tank D
= 35 u - 12 u
= 23 u
23 u = 46
1 u = 46 ÷ 23 = 2
Total volume of cooking wine in two tanks
= 60 u
= 60 x 2
= 120 ℓ
Answer(s): 120 ℓ
