Pail H and Pail J had some detergent in the ratio 7 : 5. After 35 litres of detergent was transferred from Pail H to Pail J, the volume of detergent in Pail J became 5 times as much as in Pail H. How much detergent were there in the two pails in all?
| |
Pail H |
Pail J |
Total |
Before |
7x1 =
7 u |
5x1 =
5 u |
12x1 =
12 u |
| Change |
- 35 |
+ 35 |
|
After |
1x2 =
2 u |
5x2 =
10 u |
6x2 =
12 u |
The total volume of detergent in the pails remained unchanged. Make the total volume at first and in the end the same. LCM of 6 and 12 is 12.
Amount of detergent transferred from Pail H to Pail J
= 7 u - 2 u
= 5 u
5 u = 35
1 u = 35 ÷ 5 = 7
Total volume of detergent in two pails
= 12 u
= 12 x 7
= 84 ℓ
Answer(s): 84 ℓ
