Tank K and Tank L had some vinegar in the ratio 9 : 5. After 40 litres of vinegar was transferred from Tank K to Tank L, the volume of vinegar in Tank L became 5 times as much as in Tank K. How much vinegar were there in the two tanks in all?
| |
Tank K |
Tank L |
Total |
Before |
9x3 =
27 u |
5x3 =
15 u |
14x3 =
42 u |
| Change |
- 40 |
+ 40 |
|
After |
1x7 =
7 u |
5x7 =
35 u |
6x7 =
42 u |
The total volume of vinegar in the tanks remained unchanged. Make the total volume at first and in the end the same. LCM of 6 and 14 is 42.
Amount of vinegar transferred from Tank K to Tank L
= 27 u - 7 u
= 20 u
20 u = 40
1 u = 40 ÷ 20 = 2
Total volume of vinegar in two tanks
= 42 u
= 42 x 2
= 84 ℓ
Answer(s): 84 ℓ
