Container N and Container P had some oil in the ratio 7 : 4. After 48 litres of oil was transferred from Container N to Container P, the volume of oil in Container P became 4 times as much as in Container N. How much oil were there in the two containers in all?
| |
Container N |
Container P |
Total |
Before |
7x5 =
35 u |
4x5 =
20 u |
11x5 =
55 u |
| Change |
- 48 |
+ 48 |
|
After |
1x11 =
11 u |
4x11 =
44 u |
5x11 =
55 u |
The total volume of oil in the containers remained unchanged. Make the total volume at first and in the end the same. LCM of 5 and 11 is 55.
Amount of oil transferred from Container N to Container P
= 35 u - 11 u
= 24 u
24 u = 48
1 u = 48 ÷ 24 = 2
Total volume of oil in two containers
= 55 u
= 55 x 2
= 110 ℓ
Answer(s): 110 ℓ
