Pail Y and Pail Z had some sauce in the ratio 7 : 5. After 42 litres of sauce was transferred from Pail Y to Pail Z, the volume of sauce in Pail Z became 2 times as much as in Pail Y. How much sauce were there in the two pails in all?
| |
Pail Y |
Pail Z |
Total |
Before |
7x1 =
7 u |
5x1 =
5 u |
12x1 =
12 u |
| Change |
- 42 |
+ 42 |
|
After |
1x4 =
4 u |
2x4 =
8 u |
3x4 =
12 u |
The total volume of sauce in the pails remained unchanged. Make the total volume at first and in the end the same. LCM of 3 and 12 is 12.
Amount of sauce transferred from Pail Y to Pail Z
= 7 u - 4 u
= 3 u
3 u = 42
1 u = 42 ÷ 3 = 14
Total volume of sauce in two pails
= 12 u
= 12 x 14
= 168 ℓ
Answer(s): 168 ℓ
