Container F and Container G had some detergent in the ratio 7 : 5. After 33 litres of detergent was transferred from Container F to Container G, the volume of detergent in Container G became 2 times as much as in Container F. How much detergent were there in the two containers in all?
|
Container F |
Container G |
Total |
Before |
7x1 = 7 u |
5x1 = 5 u |
12x1 = 12 u |
Change |
- 33 |
+ 33 |
|
After |
1x4 = 4 u |
2x4 = 8 u |
3x4 = 12 u |
The total volume of detergent in the containers remained unchanged. Make the total volume at first and in the end the same. LCM of 3 and 12 is 12.
Amount of detergent transferred from Container F to Container G
= 7 u - 4 u
= 3 u
3 u = 33
1 u = 33 ÷ 3 = 11
Total volume of detergent in two containers
= 12 u
= 12 x 11
= 132 ℓ
Answer(s): 132 ℓ