Container R and Container S had some cooking wine in the ratio 7 : 5. After 40 litres of cooking wine was transferred from Container R to Container S, the volume of cooking wine in Container S became 5 times as much as in Container R. How much cooking wine were there in the two containers in all?
| |
Container R |
Container S |
Total |
Before |
7x1 =
7 u |
5x1 =
5 u |
12x1 =
12 u |
| Change |
- 40 |
+ 40 |
|
After |
1x2 =
2 u |
5x2 =
10 u |
6x2 =
12 u |
The total volume of cooking wine in the containers remained unchanged. Make the total volume at first and in the end the same. LCM of 6 and 12 is 12.
Amount of cooking wine transferred from Container R to Container S
= 7 u - 2 u
= 5 u
5 u = 40
1 u = 40 ÷ 5 = 8
Total volume of cooking wine in two containers
= 12 u
= 12 x 8
= 96 ℓ
Answer(s): 96 ℓ
