Container P and Container Q had some wine in the ratio 7 : 5. After 45 litres of wine was transferred from Container P to Container Q, the volume of wine in Container Q became 5 times as much as in Container P. How much wine were there in the two containers in all?
| |
Container P |
Container Q |
Total |
Before |
7x1 =
7 u |
5x1 =
5 u |
12x1 =
12 u |
| Change |
- 45 |
+ 45 |
|
After |
1x2 =
2 u |
5x2 =
10 u |
6x2 =
12 u |
The total volume of wine in the containers remained unchanged. Make the total volume at first and in the end the same. LCM of 6 and 12 is 12.
Amount of wine transferred from Container P to Container Q
= 7 u - 2 u
= 5 u
5 u = 45
1 u = 45 ÷ 5 = 9
Total volume of wine in two containers
= 12 u
= 12 x 9
= 108 ℓ
Answer(s): 108 ℓ
