Barbara and Gillian have some pencils in the ratio 3 : 11. Barbara has 56 less pencils than Gillian. How many pencils must Gillian give to Barbara so that they will have the same number of pencils?
| |
Barbara |
Gillian |
Total |
| Before |
3 u |
11 u |
14 u |
| Change |
+ 4 u |
- 4 u |
|
After |
1x7 =
7 u |
1x7 =
7 u |
2x7 =
14 u |
The total number of pencils remains unchanged. Make the total number of pencils at first and in the end the same. LCM of 2 and 14 is 14.
Difference in the number of pencils at first
= 11 u - 3 u
= 8 u
8 u = 56
1 u = 56 ÷ 8 = 7
Number of pencils that each of them had in the end
= 14 u ÷ 2
= 7 u
Number of pencils that Gillian must give to Barbara
= 7 u - 3 u
= 4 u
= 4 x 7
= 28
Answer(s): 28
