Wendy and Yen have some files in the ratio 3 : 7. Wendy has 68 less files than Yen. How many files must Yen give to Wendy so that they will have the same number of files?
| |
Wendy |
Yen |
Total |
| Before |
3 u |
7 u |
10 u |
| Change |
+ 2 u |
- 2 u |
|
After |
1x5 =
5 u |
1x5 =
5 u |
2x5 =
10 u |
The total number of files remains unchanged. Make the total number of files at first and in the end the same. LCM of 2 and 10 is 10.
Difference in the number of files at first
= 7 u - 3 u
= 4 u
4 u = 68
1 u = 68 ÷ 4 = 17
Number of files that each of them had in the end
= 10 u ÷ 2
= 5 u
Number of files that Yen must give to Wendy
= 5 u - 3 u
= 2 u
= 2 x 17
= 34
Answer(s): 34
