Usha and Min have some markers in the ratio 3 : 7. Usha has 44 less markers than Min. How many markers must Min give to Usha so that they will have the same number of markers?
| |
Usha |
Min |
Total |
| Before |
3 u |
7 u |
10 u |
| Change |
+ 2 u |
- 2 u |
|
After |
1x5 =
5 u |
1x5 =
5 u |
2x5 =
10 u |
The total number of markers remains unchanged. Make the total number of markers at first and in the end the same. LCM of 2 and 10 is 10.
Difference in the number of markers at first
= 7 u - 3 u
= 4 u
4 u = 44
1 u = 44 ÷ 4 = 11
Number of markers that each of them had in the end
= 10 u ÷ 2
= 5 u
Number of markers that Min must give to Usha
= 5 u - 3 u
= 2 u
= 2 x 11
= 22
Answer(s): 22
