Yoko and Cindy have some markers in the ratio 5 : 13. Yoko has 64 less markers than Cindy. How many markers must Cindy give to Yoko so that they will have the same number of markers?
| |
Yoko |
Cindy |
Total |
| Before |
5 u |
13 u |
18 u |
| Change |
+ 4 u |
- 4 u |
|
After |
1x9 =
9 u |
1x9 =
9 u |
2x9 =
18 u |
The total number of markers remains unchanged. Make the total number of markers at first and in the end the same. LCM of 2 and 18 is 18.
Difference in the number of markers at first
= 13 u - 5 u
= 8 u
8 u = 64
1 u = 64 ÷ 8 = 8
Number of markers that each of them had in the end
= 18 u ÷ 2
= 9 u
Number of markers that Cindy must give to Yoko
= 9 u - 5 u
= 4 u
= 4 x 8
= 32
Answer(s): 32
