Hilda and Nicole have some markers in the ratio 5 : 11. Hilda has 66 less markers than Nicole. How many markers must Nicole give to Hilda so that they will have the same number of markers?
| |
Hilda |
Nicole |
Total |
| Before |
5 u |
11 u |
16 u |
| Change |
+ 3 u |
- 3 u |
|
After |
1x8 =
8 u |
1x8 =
8 u |
2x8 =
16 u |
The total number of markers remains unchanged. Make the total number of markers at first and in the end the same. LCM of 2 and 16 is 16.
Difference in the number of markers at first
= 11 u - 5 u
= 6 u
6 u = 66
1 u = 66 ÷ 6 = 11
Number of markers that each of them had in the end
= 16 u ÷ 2
= 8 u
Number of markers that Nicole must give to Hilda
= 8 u - 5 u
= 3 u
= 3 x 11
= 33
Answer(s): 33
