Xuan and Xandra have some pencils in the ratio 3 : 13. Xuan has 50 less pencils than Xandra. How many pencils must Xandra give to Xuan so that they will have the same number of pencils?
|
Xuan |
Xandra |
Total |
Before |
3 u |
13 u |
16 u |
Change |
+ 5 u |
- 5 u |
|
After |
1x8 = 8 u |
1x8 = 8 u |
2x8 = 16 u |
The total number of pencils remains unchanged. Make the total number of pencils at first and in the end the same. LCM of 2 and 16 is 16.
Difference in the number of pencils at first
= 13 u - 3 u
= 10 u
10 u = 50
1 u = 50 ÷ 10 = 5
Number of pencils that each of them had in the end
= 16 u ÷ 2
= 8 u
Number of pencils that Xandra must give to Xuan
= 8 u - 3 u
= 5 u
= 5 x 5
= 25
Answer(s): 25