Barbara and Hilda have some markers in the ratio 3 : 13. Barbara has 40 less markers than Hilda. How many markers must Hilda give to Barbara so that they will have the same number of markers?
| |
Barbara |
Hilda |
Total |
| Before |
3 u |
13 u |
16 u |
| Change |
+ 5 u |
- 5 u |
|
After |
1x8 =
8 u |
1x8 =
8 u |
2x8 =
16 u |
The total number of markers remains unchanged. Make the total number of markers at first and in the end the same. LCM of 2 and 16 is 16.
Difference in the number of markers at first
= 13 u - 3 u
= 10 u
10 u = 40
1 u = 40 ÷ 10 = 4
Number of markers that each of them had in the end
= 16 u ÷ 2
= 8 u
Number of markers that Hilda must give to Barbara
= 8 u - 3 u
= 5 u
= 5 x 4
= 20
Answer(s): 20
